Question

How do you evaluate `e^( ( 11 pi)/6 i) - e^( ( 3 pi)/8 i)` using trigonometric functions?

Answer 1

`: e^((11pi)/6i)-e^((3pi)/8i` `=0.483-1.424i`

Explanation:

`e^((11pi)/6i) = cos((11pi)/6) +i* sin( (11pi)/6) = 0.866 -0.5i`

`e^((3pi)/8i) = cos((3pi)/8) +i*sin( (3pi)/8) = 0.383 +0.924i`

`:. e^((11pi)/6i)-e^((3pi)/8i` `= (0.866-0.383) + (-0.5-0.924)i =0.483-1.424i`[Ans]