Question

How do you find the period of `y= 2\tan ( 3x - \frac { \pi } { 2} )`?

Answer 1

When given a tangent function of the form:

`y = Atan(Bx+C)+D`

The period is :

`p = pi/B`

Explanation:

Given: `y = 2tan(3x - pi/2)`

The period is :

`p = pi/3`

Here is a graph of the given function.

graph{y= 2tan(3x - pi/2) [-10, 10, -5, 4.995]}

Please observe that the function crosses 0 every `pi/3` units.