Question

How do you solve `sqrt4=sqrt(x+2)` and check your solution?

Answer 1

`x=2`

Explanation:

Raise both sides to the power of `^2`, doing so reduces the square roots on both sides of the equation to `1` and makes this problem simplier without changing the question.

`(sqrt4)^2=(sqrt(x+2))^2`

`4=x+2`

`x=2`

Checking the solution by substituiting `x=2` into the original problem,

`sqrt4=sqrt(2+2`

`sqrt4=sqrt4`

Therefore `x=2` is the solution