How do you combine #\frac { 6x ^ { 8} } { 4x ^ { 2} y - 12x y } + \frac { 3x ^ { 2} + 12x } { x ^ { 2} + x - 12}# into one term?

1 Answer
Apr 22, 2017

#" The Exp.="{3x(x^6+2y)}/{2y(x-3)}.#

Explanation:

#"The Expression="(6x^8)/(4x^2y-12xy)+(3x^2+12x)/(x^2+x-12),#

#=(6x^8)/{4xy(x-3)}+{3x(x+4)}/{(x+4)(x-3)},#

#=(3x^7)/{2y(x-3)}+(3x)/(x-3)#

#=(3x^7+3x*2y)/{2y(x-3)},#

#:." The Exp.="{3x(x^6+2y)}/{2y(x-3)}.#