How do you solve #\frac { 6} { u - 3} - \frac { 4} { u - 3} = 2#?

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Answer 1 · 2017-04-22T13:18:59

#color(purple)(u=4#

#6/(u-3)-4/(u-3)=2#

multiply R.H.S. and L.H.S. by #color(purple)(u-3#

#:.6-4=2(u-3)#

#:.2(u-3)=2#

#:.2u-6=2#

#:.2u=6+2#

#:.2u=8#

#:.u=8/2#

#:.color(purple)(u=4#

substitute #color(purple)(u=4#

#:.6/((color(purple)4)-3)-4/((color(purple)4)-3)=2#

#:.6/1-4/1=2#

#:.6-4=2#