What is the range of the function #f(x)=(x-3)/(x+4)#?
1 Answer
Apr 23, 2017
Explanation:
To find the value/s that y cannot be.
#"Rearrange to make x the subject"#
#y=(x-3)/(x+4)#
#color(blue)"cross-multiplying ""gives"#
#y(x+4)=x-3#
#rArrxy+4y=x-3#
#rArrxy-x=-3-4y#
#rArrx(y-1)=-3-4y#
#rArrx=(-3-4y)/(y-1)# The denominator cannot be zero. Equating the denominator to zero and solving gives the value that y cannot be.
#"solve " y-1=0rArry=1larrcolor(red)" excluded value"#
#"range is " y inRR,y!=1#