What is #x# and #y# in this system of equations: #y+x =6# and #3y -x = 3#?

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Answer 1 · 2017-04-23T16:04:53

#x=15/4#
#y=9/4#

Solve using the method of addition/ elimination

#y+x=6#
#3y-x=3#

Add the first equation to the second

#4y=9#

#y=9/4#

Substitute the value of #y# into any of the orignila equations to solve for #x#

#y+x=6#

#9/4+x=6#

#x=15/4#

Writing that as a point would be #(x,y)#

#rArr(15/4,9/4)#