How do you solve the system of equations #2x - 5y = 23# and #y = 4x + 17#?

2 Answers
Apr 24, 2017

By arranging and adding the equations #x=-6# and #y=-7#

Explanation:

The first equation is:
#5y=2x-23#
will be added to second equation after arranging it to form:
#-5y=-20x-85#
These two will yield:
#0=-18x-108# or
#18x=-108#
#x=-6#

Now solve y according to known x (for instance first given equation):
#5y=2*(-6)-23#
#5y=-35#
#y=-7#

These are your answers: #x=-6# and #y=-7#

Apr 24, 2017

#(-6,-7)#

Explanation:

#2x-5color(red)(y)=23to(1)#

#color(red)(y)=4x+17to(2)#

#"substitute " (2)" into " (1)#

#rArr2x-5(4x+17)=23#

#"distributing "#

#2x-20x-85=23#

#rArr-18x-85=23#

#"add 85 to both sides"#

#-18xcancel(-85)cancel(+85)=23+85#

#rArr-18x=108#

#"divide both sides by - 18"#

#(cancel(-18) x)/cancel(-18)=108/(-18)#

#rArrx=-6#

#"substitute this value into " (2)" and evaluate for y"#

#rArry=(4xx-6)+17=-7#

#color(blue)"As a check"#

#"substitute these values into " (1)" and if true then they are the solution"#

#(2xx-6)-(5xx-7)=-12+35=23=" right side"#

#rArr"point of intersection " =(-6,-7)#
graph{(y-4x-17)(y-2/5x+23/5)=0 [-28.87, 28.86, -14.43, 14.44]}