How do you solve the system of equations #2x - 5y = 23# and #y = 4x + 17#?
2 Answers
By arranging and adding the equations
Explanation:
The first equation is:
will be added to second equation after arranging it to form:
These two will yield:
Now solve y according to known x (for instance first given equation):
These are your answers:
Explanation:
#2x-5color(red)(y)=23to(1)#
#color(red)(y)=4x+17to(2)#
#"substitute " (2)" into " (1)#
#rArr2x-5(4x+17)=23#
#"distributing "#
#2x-20x-85=23#
#rArr-18x-85=23#
#"add 85 to both sides"#
#-18xcancel(-85)cancel(+85)=23+85#
#rArr-18x=108#
#"divide both sides by - 18"#
#(cancel(-18) x)/cancel(-18)=108/(-18)#
#rArrx=-6#
#"substitute this value into " (2)" and evaluate for y"#
#rArry=(4xx-6)+17=-7#
#color(blue)"As a check"#
#"substitute these values into " (1)" and if true then they are the solution"#
#(2xx-6)-(5xx-7)=-12+35=23=" right side"#
#rArr"point of intersection " =(-6,-7)#
graph{(y-4x-17)(y-2/5x+23/5)=0 [-28.87, 28.86, -14.43, 14.44]}