How do you solve #(3x + 1) ( x - 1) = 3x ( x - 2)#?

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Answer 1 · 2017-04-24T16:05:27

#x=1/4#

Simplify both sides by multiplying.

The left side becomes: #3x^2-2x-1#

The right side becomes: #3x^2-6x#

So this becomes:

#3x^2-2x-1=3x^2-6x#

Subtract #3x^2# on both sides:

#3x^2-2x-1-3x^2=3x^2-6x-3x^2#

Simplify to get:

#-2x-1=-6x#

Add #6x# to both sides:

#-2x-1+6x=-6x+6x#

Simplify:

#4x-1=0#

Solve for #x#:

#4x=1#

#x=1/4#