How do you write the first five terms of the sequence #a_n=3^n/(n!)#?
1 Answer
Apr 24, 2017
Explanation:
#"evaluate for " n=1,2,3,4,5#
#rArra_1=3/1=3#
#rArra_2=3^2/(2xx1)=9/2#
#rArra_3=3^3/(3xx2xx1)=27/6=9/2#
#rArra_4=3^4/(4xx3xx2xx1)=81/24=27/8#
#rArra_5=3^5/(5xx4xx3xx2xx1)=243/120=81/40#
