Question #37c70

1 Answer
Apr 24, 2017

#y=2x+1#

Explanation:

Don't worry.
This is easy to understand once you have the formulas.

We know the equation of a line is #y=mx+b#
Where #m# is the slope and #b# is the y-intercept

First, we need to find the slope.
The formula for finding the slope is #m=(y_2-y_1)/(x_2-x_1)#

Our points are #(2,5) and (0,1)#

#y_1=5# because it is your first point on #y# from #(2,5)#
#y_2=1# because it is your second point on #y# from #(0,1)#
#x_1=2# because it is your first point on #x# from #(2,5)#
#x_2=0# because it is your second point on #x# from #(0,1)#

Now lets put it into the formula

#m=(y_2-y_1)/(x_2-x_1)#

#m=(1-5)/(0-2)#

#m=(-4)/(-2)#

#m=2#

Now we take any one of our points and put it into our equation of a line

#y=mx+b#
[I am going to use our point (2,5) for #x# and #y#]
[Remember #m=2#]

#y=2x+b#

#5=(2)(2)+b#

#5=4+b# [Switch this around for clarity]

#b+4=5#

#b=5-4#

#b=1#

So we have our slope #m=2# and our y-intercept #b=1#
Now we just put it into our formula again to get the equation of the line passing through our points.

#y=mx+b#

#y=2x+1#