How do you simplify # 1 / (((11x)sqrt5)-((3y)sqrt3))#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Shwetank Mauria Apr 25, 2017 #1/(11xsqrt5-3ysqrt3)=(11xsqrt5+3ysqrt3)/(605x^2-27y^2)# Explanation: To simplify #1/(11xsqrt5-3ysqrt3)#, we should multiply numerator and denominator by conjugate of denominator i.e. #(11xsqrt5+3ysqrt3)# Hence #1/(11xsqrt5-3ysqrt3)=(11xsqrt5+3ysqrt3)/((11xsqrt5-3ysqrt3)(11xsqrt5+3ysqrt3))# = #(11xsqrt5+3ysqrt3)/((11xsqrt5)^2-(3ysqrt3)^2)# = #(11xsqrt5+3ysqrt3)/((121x^2xx5)-(9y^2xx3))# = #(11xsqrt5+3ysqrt3)/(605x^2-27y^2)# Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1001 views around the world You can reuse this answer Creative Commons License