Question #8e958

2 Answers
Apr 25, 2017

For parallel plates, we know that electric field strength E is:

E = (Delta V)/(Delta x) = 98 * 10^3 " N/C"

Balancing forces in the vertical direction:

E q = mg

q = (mg)/E = (10^(-6) * 9.81)/(98 * 10^3) approx 10^(-10) \ C

Apr 25, 2017

10^-10 C

Explanation:

Since the oildrop is at equilibrium, downward weight = upward electric force.

F_G=F_E
mg=qE
mg=qV/d
(1*10^(-6))(9.81)=q(980)/(1*10^(-2))
q=1.00*10^(-10)C