How do you sketch the graph of #y=(x-8)^2# and describe the transformation?

1 Answer
Apr 27, 2017

Draw #8# units to the right. That is the only transformation done.

Explanation:

The easiest way we can do is to graph it and describe what changes were made from the parent function, #y=x^2#.

This is a little easier because the equation given is in vertex form.

There is only thing changed:

The #h#-value. The #h#-value provides the horizontal translations, where we have to isolate the value from #x# within the bracket.

Thus, #-8 -> 8# (because we bring it over to equal to #x#).

Everything else stayed the same: #a#-value, #k#-value.

Because everything stayed the same, in terms of drawing, just draw the parabola, #8# units to the right, instead of at the origin.

Transformed function:

graph{(x-8)^2 [-10, 10, -5, 5]}

Parent function:

graph{x^2 [-10, 10, -5, 5]}

Hope this helps :)