A rectangular city lot has an area of 1000 square meters. If the length of the lot is 10 meters more than twice its width, how do you find its length and width?

1 Answer
Apr 27, 2017

Length of the Area=50 mtrs

Width of the Area =20 mtrs

Explanation:

Let the x be the length and y be the width of the Area

So we can write

x=2y+10

and

xy=1000

or

(2y+10)y=1000

or

2y^2+10y=1000

or

2y^2+10y-1000=0

or

y^2+5y-500=0

or

y^2+25y-20y-500=0

or

y(y+25)-20(y+25)=0

or

(y+25)(y-20)=0

or

y+25=0 or y-20=0

or

y=-25 Invalid value contains negative sign

or

y=20

So Width of the Area is 20 ----------Ans

By plugging the value of y=20 in the eqn x=2y+10

we get

Length of the Area=2times20+10=50-------------Ans