Question

How do you solve `x^2+5x+4=0` by graphing?

Answer 1

the zeroes are at `x=-4` and `x=-1`

Explanation:

Graph the equation and find when `y=0`:

graph{x^2+5x+4 [-5.347, 0.128, -1.328, 1.41]}

As you can see, the zeroes are at `x=-4` and `x=-1`