Question #9f5c3

Question

1044 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-04-27T20:25:13

#S={pi/12,(5pi)/12,(3pi)/4, (13 pi)/12,(17 pi)/12, (7pi)/4}#

#cot 3x =1#

#3x=cot^-1 1#

#3x=tan^-1 (1/1)#

#3x=tan^-1 1#

#3x=pi/4 + pi n#

#x=(pi/4 + pi n)/3#

#x=pi/12 + pi/3 n#, where n are integers

#n=0, x=pi/12#

#n=1, x = (5pi)/12#

#n=2, x = (3pi)/4#

#n=3, x = (13 pi)/12#

#n=4, x = (17 pi)/12#

#n=5,x= (7pi)/4#

#S={pi/12,(5pi)/12,(3pi)/4, (13 pi)/12,(17 pi)/12, (7pi)/4}#