Question

Determine the density of chlorine gas at 22.0°C at 1 ATM?

Answer 1

Well, since `PV=nRT`, `rho~=3*g*L^-1`

Explanation:

If `PV=nRT` by the Ideal Gas equation, then.............

`P/(RT)=n/V=("mass"/"molar mass")/V`..........and

Thus, `(P)/(RT)xx"molar mass"="mass"/"volume"=rho, "i.e. density."`

So thus `rho=(1*atmxx70.9*g*mol^-1)/(0.0821*(L*atm)/(K*mol)xx295*K)=2.93*g*L^-1`

`"Is the molar mass of chlorine gas correct? Why?"`