How do you solve the equation #4x^2=20x-25# by completing the square?

Question

4270 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-04-29T04:18:40

#5/2#

given,#4x^2 = 20x -25 #

#rArr 4x^2-20x+25 = 0#

#rArr(2x)^2-2*2x*5+(5)^2=0#

#rArr(2x-5)^2=0#

#rArr (2x-5)=sqrt0 = 0#

#rArr 2x = 5#

#rArrx =5/2#