Question

If a `2.96*g` mass of potassium chloride, and a `1.92*g` mass of dioxygen gas react, what mass of `"potassium chlorate"` results?

Answer 1

`x<=............5*g`

Explanation:

There are `x*g` `KClO_3`...........

And we recover `(2.96*g)/(74.55*g*mol^-1)=0.0397*mol` with respect to `KCl`.

And `(1.92*g)/(15.999*g*mol^-1)=0.120*mol` with respect to `"oxygen"`.

Clearly, there were `0.0397` `"mol"` with respect to `KClO_3`.

And thus `x`, `"mass of potassium chlorate"` `=` `0.0397*molxx122.55*g*mol^-1=4.86*g`