How do you simplify #\frac { 10v ^ { 2} - 20v } { 3v ^ { 2} - 3v - 6}#?

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Answer 1 · 2017-04-29T23:35:58

See the entire solution process below:

First, rewrite the expression by factoring the numerator and denominator as:

#(10v(v - 2))/((v - 2)(3v + 3))#

Next, cancel the common terms in the numerator and denominator:

#(10vcolor(red)(cancel(color(black)((v - 2)))))/(color(red)(cancel(color(black)((v - 2))))(3v + 3)) =>#

#(10v)/(3v + 3)# Where #v != 2# and #v != -1#

Or, factoring a #3# out of the term in the denominator:

#(10v)/(3(v + 1))# Where #v != 2# and #v != -1#