Question #1f9b2
1 Answer
Explanation:
The first thing you need to do here is to figure out the number of milligrams of solute present in the
As you know, solutions are homogeneous mixtures, which means that they have the same composition throughout. You can thus use the initial concentration of the solution to figure out the mass of the solute in the first aliquot
#20 color(red)(cancel(color(black)("mL"))) * (1 color(red)(cancel(color(black)("L"))))/(10^3color(red)(cancel(color(black)("mL")))) * "1000 mg"/(1 color(red)(cancel(color(black)("L")))) = "20 mg"#
Now, you dilute this aliquot to a final volume of
This means that the standard
Consequently, the
#15 color(red)(cancel(color(black)("mL"))) * "20 mg"/(100color(red)(cancel(color(black)("mL")))) = "3 mg"#
of solute. You dilute this solution to a final volume of
Now, use the known composition of the Standard
#1 color(red)(cancel(color(black)("L"))) * (10^3 color(red)(cancel(color(black)("mL"))))/(1color(red)(cancel(color(black)("L")))) * "3 mg"/(100 color(red)(cancel(color(black)("mL")))) = "30 mg"#
Therefore, you can say that the concentration of the Standard
#color(darkgreen)(ul(color(black)("Standard B" = "30 mg L"^(-1))))#