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Question #f7484

1 Answer

May 1, 2017

#(tan^2x)^'=2tanxsec^2x#

Explanation:

Apply the chain rule to differentiate:

#([f(x)]^n)^'=n[f(x)]^(n-1)f^'(x)#

#(tan^2x)^'=2tanxsec^2x#

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