Question

What is the standard form of `y= (x-14)(x-2)`?

Answer 1

`y=x^2-16x+28`

Explanation:

To find the standard form from this form (factored form), we simply multiply the sets of brackets. If you're unsure how to do that, see this link

`y=(x-14)(x-2)`
`y=x^2-14x-2x+28`
Then collect the x terms, to get:
`y=x^2-16x+28`

Answer 2

See the entire solution process below:

Explanation:

To get to the standard form of the equation you must multiply the two terms on the right side of the equation:

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

`y = (color(red)(x) - color(red)(14))(color(blue)(x) - color(blue)(2))` becomes:

`y = (color(red)(x) xx color(blue)(x)) - (color(red)(x) xx color(blue)(2)) - (color(red)(14) xx color(blue)(x)) + (color(red)(14) xx color(blue)(2))`

`y = x^2 - 2x - 14x + 28`

We can now combine like terms:

`y = x^2 + (-2 - 14)x + 28`

`y = x^2 + (-16)x + 28`

`y = x^2 - 16x + 28`