Question

How do you solve `x^2-2x=5` using the quadratic formula?

Answer 1

`x=4` and `x=0`

Explanation:

In quadratic equations we have a formulae to find the roots of the quadratic expression `ax^2+bx+c=0` that is:
`x=[(-b)+-(sqrt(b^2-4ac))]/(2a)`
So extracting the values from the given above equation and substituting we get
`x=[-(-2)+-(sqrt(((-2)^2)-4(1)(-5)))]/[2(1)]`
`x=(2-2)/2`,`x=(2+2)/2`
`=>x=4,0`