Question

If `f(x)=3x^2 - 3x`, what is f(0), f(-1) and f(2)?

Answer 1

`f(0)=0`
`f(-1)=6`
`f(2)=6`

Explanation:

`f(x)=3x^2-3x`

`f(0)=3*0^2-3*0=0`

`f(-1)=3*(-1)^2-3*(-1)=3*1+3=6`

`f(2)=3*2^2-3*2=3*4-6=12-6=6`