How do you solve #3z ( z + 4) ( z - 1) = 0#?

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Answer 1 · 2017-05-04T17:30:02

See the solution process below:

To solve this problem equate each term on the left side of the equation to #0# and solve for #z#:

Solution 1)

#3z = 0#

#(3z)/color(red)(3) = 0/color(red)(3)#

#(color(red)(cancel(color(black)(3)))z)/cancel(color(red)(3)) = 0#

#z = 0#

Solution 2)

#z + 4 = 0#

#z + 4 - color(red)(4) = 0 - color(red)(4)#

#z + 0 = -4#

#z = -4#

Solution 3)

#z - 1 = 0#

#z - 1 + color(red)(1) = 0 + color(red)(1)#

#z - 0 = 1#

#z = 1#

The solution is: #z = 0#, #z = -4#, #z = 1#