What is the equation of the line that goes through the point (3,2) and has a slope of -3/2?

1 Answer
May 4, 2017

y-2=(-3/2)(x-3)
or
y=(-3x)/2+13/2

Explanation:

Plug into point-slope form which is:

y-y_1=m(x-x_1)

Plugging in will give you:

y-2=(-3/2)(x-3)

If you want, you can put this in point-intercept form by solving for y:

y-2=(-3/2)x+(9/2)

y=(-3x)/2+13/2