What is the equation of the line that goes through the point #(3,2)# and has a slope of #-3/2#?

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Answer 1 · 2017-05-04T20:39:44

#y-2=(-3/2)(x-3)#
or
#y=(-3x)/2+13/2#

Plug into point-slope form which is:

#y-y_1=m(x-x_1)#

Plugging in will give you:

#y-2=(-3/2)(x-3)#

If you want, you can put this in point-intercept form by solving for #y#:

#y-2=(-3/2)x+(9/2)#

#y=(-3x)/2+13/2#