What is the equation of the line that goes through the point #(3,2)# and has a slope of #-3/2#?

1 Answer
May 4, 2017

#y-2=(-3/2)(x-3)#
or
#y=(-3x)/2+13/2#

Explanation:

Plug into point-slope form which is:

#y-y_1=m(x-x_1)#

Plugging in will give you:

#y-2=(-3/2)(x-3)#

If you want, you can put this in point-intercept form by solving for #y#:

#y-2=(-3/2)x+(9/2)#

#y=(-3x)/2+13/2#