How do you simplify #((x-3)/(x^2+3x+2))/((x^2-9)/(x+1))#?

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Answer 1 · 2017-05-05T03:55:46

I tried this:

We can write it rearranging:

#(x-3)/((x+1)(x+2))*(x+1)/((x+3)(x-3))#

where we changed the fraction into a multiplication.

We may now simplify:

#cancel((x-3))/(cancel((x+1))(x+2))*cancel((x+1))/((x+3)cancel((x-3)))#

and be left with:

#1/((x+2)(x+3))#