How do you solve #2( - 5x + 1) = 82#?

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Answer 1 · 2017-05-05T20:31:23

#x=-8#

Divide both sides by #2#,

#1/2*2(-5x+1)=82/2#

#cancel1/cancel2*cancel2(-5x+1)=41#

#-5x+1=40#

Subtract #1# from both sides,

#-5x+1-1=41-1#

#-5x+cancel1-cancel1=40#

#-5x=40#

Divide both sides #-5#

#(-5x)/(-5)=40/-5#

#(-cancel5x)/(-cancel5)=-8#

#x=-8#