How do you solve (n-27)^(3/2) = 64?

1 Answer
May 5, 2017

n=43

Explanation:

Proceed as follows

Raise both sides of the equation to the 2/3 power

[(n-27)^(3/2)]^(2/3)=(64)^(2/3)

Using properties of exponents rewrite

n-27=[64^(1/3)]^2

The cube root of 64 is 4

n-27=(4)^2

n-27=16

n=27+16=43