How to integrate ? int_0^oo 1/(1+e^x)*dx
1 Answer
May 6, 2017
Explanation:
First working with the indefinite integral, divide the numerator and denominator by
Let
=-int(-e^-x)/(e^-x+1)dx=-int1/udu=-lnabsu
=-ln(e^-x+1)+C
So:
=(lim_(xrarroo)(-ln(e^-x+1)))-(-ln(e^0+1))
Note that
=-ln(1)+ln(1+1)
=ln(2)