How do you solve #log_3 15#? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer Binayaka C. May 6, 2017 #log_3 15 = 2.46497352# Explanation: Let #log_3 15 =x :. 3^x=15 #.Taking log on both sides , we get #x log 3 = log 15 :. x= log 15/log 3 # #= 1.17609126/0.477121255=2.46497352#[Ans] Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve #9^(x-4)=81#? How do you solve #logx+log(x+15)=2#? How do you solve the equation #2 log4(x + 7)-log4(16) = 2#? How do you solve #2 log x^4 = 16#? How do you solve #2+log_3(2x+5)-log_3x=4#? See all questions in Logarithmic Models Impact of this question 3776 views around the world You can reuse this answer Creative Commons License