How do you simplify #(-7)(1/14)(-11)#?

2 Answers
May 6, 2017

Multiply the numerators and then multiply the denominators.

Explanation:

Although it is not written, the denominator of #-7# and #-11# is #1#.
So it looks like this:
#(-7/1)(1/14)(-11/1)#

Then you have to multiply the numerators and the denominators.
Like this:
#(-7*1*-11)/(1*14*1)#

Once you multiply them you will get:
#77/14#

But, this is not your final answer. It can be simplified because 77 and 14 are both multiples of 7.
So the simplified improper fraction is:
#11/2#
As a mixed fraction, it would look like:
#5##1/2#
As a decimal, it would look like:
#5.5#

Hope this helps :)

#11/2 =5 1/2#

Explanation:

The expression can be written as:

#(-7)/1 xx 1/14 xx (-11)/1" "larr# the sign will be positive

Cancel any like factors in the numerator and denominator.
This makes the numbers smaller and easier to simplify.

#cancel7/1 xx 1/cancel14_2 xx 11/1#

Now multiply straight across:

#=11/2#

#= 5 1/2#

# = 5.5#