Question

How do you solve `7(4x +9)-13=-87`?

Answer 1

`-4.89` or `-137/28`

Explanation:

Start with the easiest step, which is adding `13` to both left hand side and right hand side.

`7(4x+9) cancel(-13 + 13) = -87 + 13`
`7(4x+9) = -74`

Next, divide both LHS and RHS by `7`

`(cancel7(4x+9))/cancel7 = -74/7`
`4x+9 = -74/7`

Subtracting LHS and RHS by `9`,

`4x cancel(+9-9) = (-74/7)-9`
`4x = -137/7`

Dividing LHS and RHS by `4`,

`cancel4x/cancel4 = -137/28`
`x = -137/28 or -4.89`

Answer 2

See below

Explanation:

First of all you will have to expand your bracket and this is how you will get a normal solving equation and be able to find what `x` is.
To expand the bracket you have to know that you need to multiply everything inside the bracket by the outside:
`7(4x+9)-13=-87`
`28x+63-13=-87` Expand the bracket

`28x+63=-74` Get rid of -13 by ading it to both sides because you have to always do the same to both sides of the equal sign. Therefore if you have -13 you +13.
`28x=-137` You then subtract 63 because you need `x` on its own. To do this you look at the sign before the number 63, in this case you have +63 which means you have to subtract 63 and you get that `28x=-137` and you divide by how many `x` you have to find what 1 `x` is
`x=-4.892857143`
or round it `-4.9`
I hope this helps you!

Answer 3

`color(blue)(x=4.893` to the nearest 3 decimal places

Explanation:

`7(4x+9)-13=-87`

`:.28x+63-13=-87`

`:.28x=-87-63+13`

`:.28x=-150+13`

`:.28x=-137`

`:.x=-137/28`

`:.color(blue)(x=4.893` to the nearest 3 decimal places