A charge of #12 C# passes through a circuit every #9 s#. If the circuit can generate #6 W# of power, what is the circuit's resistance?

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Answer 1 · 2017-05-07T14:43:32

The resistance is #=3.375 Omega#

The charge is

#Q=It#

the current is #I=Q/t#

The power is

#P=UI#

But

According to Ohm's Law

#U=RI#

So,

the power is #P=RI*I=RI^2#

the resistance is #R=P/I^2=P/(Q/t)^2#

#=6/(12/9)^2#

#=6*81/144#

#=3.375 Omega#