How do you solve the following system?: -x+6y= - 2 , 5x - 2y= 3 x+6y=2,5x2y=3

1 Answer
May 7, 2017

Make the first equation x=6y+2x=6y+2 and substitute into the second equation.

Explanation:

By adding x and 2 to both sides of the first equation, we get:
x=6y+2x=6y+2
Now we substitute this expression of x into the second equation to get:
5(6y+2)-2y=35(6y+2)2y=3 which we can distribute the 5 on the left hand side to get:
30y+10-2y=330y+102y=3 which we combine the y-terms on the left hand side and subtract 10 from both sides:
28y=-728y=7 by dividing both sides by 28, we get:
y=-1/4y=14

By substituting this value of y into the x=6y+2x=6y+2 equation, we get:
x=6(-1/4)+2x=6(14)+2
x=-3/2+2x=32+2
x=1/2x=12
Therefore, our answer is the coordinate point (1/2, -1/4)(12,14)