A charge of #30 C# passes through a circuit every #5 s#. If the circuit can generate #42 W# of power, what is the circuit's resistance?

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Answer 1 · 2017-05-08T18:14:14

#R= 7/6Omega#

Current is charge divided by time:

#I = (30"C")/(5"s") = 6"A" #

Power it the square of the current multiplied by the resistance:

#P = I^2R#

#42"W" = (6"A")^2R#

#R= 42/36Omega#

#R= 7/6Omega#