Question

Question #ad885

Answer 1

The pressure of the gas is 192 bar.

Explanation:

This looks like the time to apply the Ideal Gas Law:

`color(blue)(bar(ul(|color(white)(a/a)pV = nRTcolor(white)(a/a)|)))" "`

where

• `p` is the pressure
• `V` is the volume
• `n` is the number of moles
• `R` is the gas constant
• `T` is the temperature

We can rearrange the Ideal Gas Law to get

`P = (nRT)/V`

In this problem,

`n = "4.35 mol"`
`R = "0.0831 4 bar·L·K"^"-1""mol"^"-1"`
`T = "(75 + 273.15) K" = "348.15 K"`
`V = "0.655 L"`

∴ `P = (4.35 color(red)(cancel(color(black)("mol"))) × "0.083 14 bar"·color(red)(cancel(color(black)("L·K"^"-1""mol"^"-1"))) × 348.15 color(red)(cancel(color(black)("K"))))/(0.655 color(red)(cancel(color(black)("L")))) = "192 bar"`