How do you solve #\frac { 32} { h + 1} - \frac { 35} { h } = - 1#?

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Answer 1 · 2017-05-10T05:21:39

#h=7; h=-5#

Given: #32/(h+1)-35/h=-1#

Multiply both sides by #h(h+1)#:

#32hcancel(h+1)/cancel(h+1)-35cancel(h)(h+1)/cancel(h)=-h(h+1)#

#32h-35h-35=-h^2-h#

#-3h-35=-h^2-h#

#h^2-2h-35=0#

#(h-7)(h+5)=0#

#h=7; h=-5#

To check, substitute answers into the #given# equation:

#32/(h+1)-35/h=-1#

#32/(7+1)-35/7=-1#

#4-5=-1#

#-1=-1#

~~~~~

#32/(-5+1)-35/(-5)=-1#

#32/(-4)-35/(-5)=-1#

#-8+7=-1#

#-1=-1#