How do solve the following linear system?: # x - 3y = 8 , 8x+2y=2 #?

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Answer 1 · 2017-05-13T14:10:06

#x=11/13,y=-(31/13)#

We can solve this using elimination of variables. We can multiply#x-3y=8# by #8# to get #8x-24y=64#. We can then subtract the two equations:

#(8x+2y=2)-(8x-24y=64) => 26y=-62#

Dividing both sides of the equation by 26, we get:

#y=-(62/26) =>y = -(31/13)#

Substituting the value of #y# into the first equation, we get:

#x-3(-(31/13))=8=>x+93/13=8#

#x=8-93/13=>x=104/13-93/13#

#x=11/13#