How do you divide #\frac { 4x ^ { 2} - 12x } { x ^ { 2} } \div \frac { 3x - 9} { 8x }#?

1 Answer
Barney V.
May 14, 2017

#color(blue)(32/3# or #color(blue)(10 2/3#

Explanation:

#(4x^2-12x)/x^2-:(3x-9)/(8x)#

#:.=(4x^2-12x)/x^2 xx (8x)/(3x-9)#

#:.=(4x(cancel(x-3)))/x^2 xx (8x)/(3(cancel(x-3)))#

#:.=(32cancel(x^2))/(3cancel(x^2))#

#:.=color(blue)(32/3# or #color(blue)(10 2/3#

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