Question

How do you solve `\frac { 1} { y } + \frac { 1} { y + 8} = \frac { 1} { 11}`?

Answer 1

First, note that `y` cannot be equal to `0` or `-8`

Then, multiply both sides by `11*y*(y+8)`, you get :

`11(y+8) + 11y = y(y+8)`
`<=>`
`22y+88 = y^2 + 8y`
`<=>`
`y^2 - 14y - 88 = 0`

Then you have a quadratic equation.