Question

How do you find the discriminant for `0.2x^2-1.5x+2.9=0` and determine the number and type of solutions?

Answer 1

see explanation

Explanation:

`0.2x^2-1.5x+2.9=0`

To find the discriminant of an equation,
first, you must make the equation into the form of
`ax^2+bx+c=0`
And the discriminant will be `b^2-4ac`

if the discriminant =0,then the equation has two equal real roots
if the discriminant >0,the the equation will have two different real roots
if the discriminant < 0, the the equation will have no real roots.

so based on the given equation
we can write out that
discriminant=`(-1.5)^2-4(0.2)(2.9)`
=-0.07
because the discriminant of the equation is < 0
so we can tell that the equation has no real roots.