How do you simplify #(\frac { 2a ^ { 2} \cdot 2a b ^ { 2} } { a ^ { 4} b ^ { 5} } ) ^ { 3}#?

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Answer 1 · 2017-05-15T10:40:24

#64/(a^3b^9)#

#2a*2ab^2=4a^3b^2# (To multiply two numbers with indices, add the powers)

Take away #b^2# from the numerator AND the denominator.
(To divide numbers with indices, subtract the powers)

Take away #a^3# from the numerator AND the denominator.

Then, cube the numerator AND the denominator

#4^3 = 64#
#a(b^3)^3 = a^3b^9#

And that's our answer.

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