Question #fbcc4

Question

1999 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-05-15T22:48:40

P = 28 Atm (2 sig. figs.) but exact sig. figs. could be based upon the V = 500 ml data point => 1 sig. fig. => P = 30 Atm.

Using the Ideal Gas Law PV = nRT solve for P = nRT/P

n = #("moles" ) CO_2#(gas) = #(25 g) / (44 (g/(mol))# = #0.5681 "mole"#

#R = "gas"."constant" = 0.08206 "L-Atm"/"mol-K"#

#T = Temperature ("Kelvin") = (25 + 273)K = 298K#

#V = Volume (Liters) = (500/1000) Liters = 0.500 "Liters"#

#P = [(0.5681 "mole")(0.08206 "L-Atm"/"mol-K")(298 K)] / [(0.500 L)]#

= #27.7885 Atm => 28 Atm (2 sig. figs.) or ~ 30 Atm (1 sig. fig.)#