Question

Question #70cfb

Answer 1

`10^(23) prot ons` (order of magnitude, you asked)

Explanation:

If one proton has a mass of `1.67 xx 10^-27 kg`, and there are `10^3` grams in one kilogram, one gram of protons contains

`1 g((1kg)/(10^3g))((1 prot on)/(1.67 xx 10^(-27)kg)) = 6.00 xx 10^23 prot ons`

and the order of magnitude is thus in `10^23`