Question #2867e Trigonometry 1 Answer salamat May 16, 2017 sin theta = -3/sqrt 10sinθ=−3√10 sec theta = -sqrt10secθ=−√10 Explanation: since tan thetatanθ is +ve value and cos theta < 0cosθ<0, it situated in 3rd quadrant. tan thetatanθ = opposite / adjacent =(-3)/-1 = 3−3−1=3 hypotenuse = sqrt(_3^2 + -1^2 )= sqrt 10=√_32+−12=√10 therefore, sin thetasinθ = opposite/hypotenuse = -3/sqrt 10=−3√10 sec thetasecθ = hypotenuse/adjacent = sqrt10/-1 = -sqrt10=√10−1=−√10 Answer link Related questions How do I determine the molecular shape of a molecule? What is the lewis structure for co2? What is the lewis structure for hcn? How is vsepr used to classify molecules? What are the units used for the ideal gas law? How does Charle's law relate to breathing? What is the ideal gas law constant? How do you calculate the ideal gas law constant? How do you find density in the ideal gas law? Does ideal gas law apply to liquids? Impact of this question 1562 views around the world You can reuse this answer Creative Commons License