Question #2867e

1 Answer
May 16, 2017

sin theta = -3/sqrt 10sinθ=310

sec theta = -sqrt10secθ=10

Explanation:

since tan thetatanθ is +ve value and cos theta < 0cosθ<0, it situated in 3rd quadrant.

tan thetatanθ = opposite / adjacent =(-3)/-1 = 331=3

hypotenuse = sqrt(_3^2 + -1^2 )= sqrt 10=_32+12=10

therefore,

sin thetasinθ = opposite/hypotenuse = -3/sqrt 10=310

sec thetasecθ = hypotenuse/adjacent = sqrt10/-1 = -sqrt10=101=10