Question #2867e

1 Answer
salamat
May 16, 2017

#sin theta = -3/sqrt 10#

#sec theta = -sqrt10#

Explanation:

since #tan theta# is +ve value and #cos theta < 0#, it situated in 3rd quadrant.

#tan theta# = opposite / adjacent =#(-3)/-1 = 3#

hypotenuse #= sqrt(_3^2 + -1^2 )= sqrt 10#

therefore,

#sin theta# = opposite/hypotenuse #= -3/sqrt 10#

#sec theta# = hypotenuse/adjacent # = sqrt10/-1 = -sqrt10#

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