How do you solve #2sinthetacostheta +costheta=0#?

1 Answer
May 17, 2017

#theta=pi/2+npi, 11pi/6+2npi, 7pi/6+2npi#

Explanation:

Factor out a #costheta#:

#(costheta)(2sintheta+1)=0#

Now solve for each of these:

#costheta=0#

This happens when #theta=pi/2+npi# where #n# is a whole number.

#2sintheta+1=0#

#sintheta=-1/2#

This happens at #theta=7pi/6+2npi# and #theta=11pi/6+2npi#